3t^2+30t=0

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Solution for 3t^2+30t=0 equation: 



3t^2+30t=0

a = 3; b = 30; c = 0;
Δ = b2-4ac
Δ = 302-4·3·0
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$


$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-30}{2*3}=\frac{-60}{6}
=-10
$


$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+30}{2*3}=\frac{0}{6}
=0
$

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